LUX compared to Watts

Lumens, lux, watt? It is easy to get confused about the different terms that are used, when purchasing a light or bulb. Read more in this article about 3 of the terms,

  1. Lumens
  2. Lux
  3. Watt

Lumens and light

Luminous flux is know as Lumens and is also a unit of (led)light

lumens photoLumens is a measuring unit, which tells the total amount of light emitted from a flashlight, bulb or headlamp. It is possible to roughly state that the more Lumens the brighter the light. Whenever we test and compare products, we make use of lumens to determine the entire quantity of led light output. But lumens is only going to show us a part of the picture. Producing and creating a perfect beam pattern does not reveal enough information to show how the light output is created. For this we have to use a lux meter. When we measure the volume of lumens, we use a highly specialised light-weight sphere. Expensive but very adequate equipment. Most flashlights, bulbs and headlamps quickly fall in lumens and promise a higher lumens output than they can accomplish. To avoid this in products, (beauty) manufacturers carry out light-weight assessments on all of their led light products to ensure the lumens amount is absolutely correct. To get a constant light output, they utilize a Continuous Current Output technology in goods in order to get the highest possible light result for the entire life of the battery.


Can I make use of Watt to determine the power of  a light?

Watt is really a unit for energy usage

watt photoThe short answer is simply no, Watt demonstrates how much energy the product uses, not just how much light output (lumens) it gives you. These are completely different things. That is why you should not look for the quantity of watt consumed, when shopping for an Aduro Led mask or for any kind of light. It will only let you know how quickly it will drain the battery, rather than just how much light it produces. Additionally it is worth to know that 1Watt halogen and 1 Watt LED will not produce the same amount of light. The LED Chip is a lot more efficient and will convert much more energy to light compared to halogen bulb. It is essential to keep in mind that the more power consumed the more heat will be produced, and heat will always result in a loss of energy. Although when you are on a holiday heat gives you energy 😉 it will calm you as if you were in Hypnose Amsterdam. For this reason many flashlights and headlamps come with an excellent metal heat sink, which uses the whole device to efficiently divert the heat through the entire core construction. This can ensure a stable light output for a much longer period of time, and prolong the life time of the LED Chip. This is much more cost-efficient.

Exactly how much light does it provide?

The quantity of light that you get depends of your source

To be able to visualise how much light a product provides, it is important to understand what the quantity of lumens it corresponds to. On the chart you can see common known items and how much light they emit measured in lumen. Use these typical known items as a guide to how much light you need. Remember that numerous manufactors promise a higher lumen output than the product actually can deliver. It is a good idea to look after the Light Curve on the given product. When this is not available, we recommend you to contact and ask the manufacturer of beauty products. Or justask Brady. He knows all.

For the die hards…

Calculate LUX to Watts yourself

Lux to watts calculation formula

Lux to watts calculation with area in square feet.
The power P in watts (W) is equal to the 0.09290304 times the illuminance Ev in lux (lx) times the surface area A in square feet (ft2), divided by the luminous efficacy η in lumens per watt (lm/W):
P(W) = 0.09290304 × Ev(lx) × A(ft2) / η(lm/W)
Lux to watts calculation with area in square meters
The power P in watts (W) is equal to the illuminance Ev in lux (lx) times the surface area A in square meters (m2), divided by the luminous efficacy η in lumens per watt (lm/W):
P(W) = Ev(lx) × A(m2) / η(lm/W)

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